Mysql database

ok on tuts.php heres the code

<?

 $host = "localhost" ;
$user = "******" ;
$pass = "******" ;
$db = "tuts" ;
$table = "php" ;
$show_all = "SELECT * FROM $table" ;

mysql_connect ($host,$user,$pass) or die ( mysql_error ());
mysql_select_db ($db)or die ( mysql_error ());
$result = mysql_query ($show_all) or die ( mysql_error ());
while ($row = mysql_fetch_array ($result))
{
$view_db .= "Tutorial Name: ".$row[ "tutn" ]."<br>";
$view_db .= "Website: ".$row[ "ws" ]."<br>";
$view_db .= "Tutorial Number: ".$row[ "id" ]."<br>";
}
echo ( "$view_db" );

?>

that works fine.. thats getting the information out of the database
its getting tutorial name, website, tutorial number out of it but theres tutorial in there to i dont want that listed on that page...

now showtuts.php
i dont have anything there yet.

i need to make it so that on tuts.php it shows the tutorial name as a link to showtut.php?id=1 like that if thats the tutorial number its actually the id INT

what would i put on showtuts.php to show the tutorial?

like this

Tutorial Name: Testing Name (the actual name Testing Name is a link to that tutorial
Website: that shows the persons website as a link
Tutorial #: shows the id of it

on showtuts.php i want whatever tutorial name they click on that tutorial comes up..

this is all mysql not query strings.
sorry for the long post though

On showtuts.php, you'd have to do something like:
<?
if ($id) {
$sql = "SELECT fields FROM table WHERE id = $id";
$sql2 = mysql_query($sql);
$sql3 = mysql_fetch_array($sql2);
echo "$sql3[field]";
}
?>